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Find the derivative of
f(x)=(arccost)second power

User Sokolof
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1 Answer

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Answer:


\displaystyle f'(t) = (-2 \arccos t)/(√(1 - t^2))

General Formulas and Concepts:

Calculus

Differentiation

  • Derivatives
  • Derivative Notation

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]:
\displaystyle (d)/(dx)[f(g(x))] =f'(g(x)) \cdot g'(x)

Explanation:

Step 1: Define

Identify


\displaystyle f(t) = (\arccos t)^2

Step 2: Differentiate

  1. Basic Power Rule [Derivative Rule - Chain Rule]:
    \displaystyle f'(t) = 2 \arccos t (\arccos t)'
  2. Trigonometric Differentiation:
    \displaystyle f'(t) = (-2 \arccos t)/(√(1 - t^2))

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

User Dgor
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