8x^2-2x-1=0 find the solution

asked Oct 20, 2018 3.2k views

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8x² - 2x - 1 = 0
8x² - 4x + 2x - 1 = 0
4x (2x - 1) + 1 (2x - 1) = 0
(4x + 1)(2x - 1) = 0

4x + 1 = 0 or 2x - 1 = 0
x = -1/4 0r x = 1/2

David Conde answered Oct 26, 2018

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