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What volume of 0.210 M sulfuric acid is required to completely react with 2.14 g aluminium hydroxide?
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What volume of 0.210 M sulfuric acid is required to completely react with 2.14 g aluminium hydroxide?

User Gabe Halsmer
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1 Answer

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3 H2SO4 + 2 Al(OH)3 → Al2(SO4)3 + 6 H2O

(2.14 g Al(OH)3) / (78.0036 g Al(OH)3/mol) x (3 mol H2SO4 / 2 mol Al(OH)3) / (0.210 mol/L H2SO4) =
0.19596 L = 196 mL H2SO4
User Nick Van Hoogenstyn
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