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if the volume of a cone is 108 pi cubic units and the radius is 6 units what is the height of the cylinder

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$$\begin{matrix} V=\pi r^2\left((h)/(3)\right)\\\\ 108=\pi \left(6\right)^2\left((h)/(3)\right)\\\\ \pi \left(6\right)^2\left((h)/(3)\right)=108\\\\ \pi \left(36\right)\left((h)/(3)\right)=108\\\\ 12\pi h=108\\\\ (12\pi h)/(12\pi )=(108)/(12\pi )\\\\ h=(9)/(\pi )\\\\ \mathbf{h\approx 2.86\:units} \end{matrix}$$
User Lukecampbell
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