Question

The braking distance d, in meters, of a vehicle traveling at a velocity v, in meters per second, is given by the formula

Answer 1

Given:

Speed of car is

`57\text{ }(km)/(hr)=15.83(m)/(s)`
`g\approx9.8\text{ }(m)/(s^2)`
`\mu=0.8`

Required:

Breaking distance d

Step-by-step explanation:

We have formula to find the breaking distance

`d=(v^2)/(2\mu g)`

substitute the values

`d=(15.83^2)/(2*0.8*9.8)=15.98\approx16m`

Final answer:

Breaking distance of car at speed 57 kmph with 0.8 friction is 16 m approximately.