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If you have two six-sided die each labelled one throgh six. Which set of independent events has a higher probabllity?

User Mayersdesign
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1 Answer

19 votes
19 votes

SOLUTION

We will consider all the sets of probabilities, the one with the highest probability is the right answer.

a) You roll an odd number and roll a 5: the probability is calculated thus:


\begin{gathered} (3)/(6)*(1)/(6) \\ =(3)/(36) \\ =(1)/(12) \\ =0.0833 \end{gathered}

b) You land on an odd number or you roll a 6: the probability is calculated thus:


\begin{gathered} (3)/(6)+(1)/(6) \\ =(4)/(6) \\ =(2)/(3) \\ =0.6667 \end{gathered}

c) You roll a six and roll a 4: the probability is calculated thus:


\begin{gathered} (1)/(6)*(1)/(4) \\ =(1)/(24) \\ =0.0417 \end{gathered}

d) You roll a 3 and roll an old number: the probability is calculated thus:


\begin{gathered} (1)/(6)*(3)/(6) \\ =(3)/(36) \\ =(1)/(12) \\ =0.0833 \end{gathered}

Now, comparing all the probabilities, the set of independent events with the highest probability is the event of You land on an odd number or you roll a 6.

Therefore the correct answer is B.

User JadziaMD
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