Part 1)
Let
x-------> the length of the rectangle
y-------> the width of the rectangle
we know that
the area of the rectangle is equal to

------> equation A
when

substitute the value of y in the equation A

Find the area

therefore
the answer Part 1) is the option A

Part 2)
we know that
the rate of dives is

The linear equation is

where
x------> is the time in seconds
y-----> is the depth in meters
For

convert to seconds

substitute in the linear equation

therefore
the answer part 2) is the option A
