Question

If 2.0 mol of an ideal gas are at an initial temperature of 250 k and a pressure of 1.5 atm, what is the gas volume?

Answer 1

Use the equation pv=nrt.
in this case, you're looking for V. so v=nrt/p.

Answer 2

Answer: The volume of gas is 27.36 L

Step-by-step explanation:

To calculate the volume of gas, we use the equation given by ideal gas equation:

PV = nRT

where,

P = Pressure of the gas = 1.5 atm

V = Volume of the gas = ?

n = Number of moles of gas = 2.0 mol

R = Gas constant =
`0.0821\text{ L atm }mol^(-1)K^(-1)`

T = Temperature of the gas = 250 K

Putting values in above equation, we get:

`1.5atm* V=2.0mol* 0.0821\text{ L atm }mol^(-1)K^(-1)* 250K\\\\V=(2.0* 0.0821* 250)/(1.5)=27.36L`

Hence, the volume of gas is 27.36 L