Question

Please help me in this problem using a 6th grade formula.

Answer 1

Given:

The dimensions of the triangle:

Base b = 4 in

Height h = 3 in

The dimensions of the rectangle:

Length l = 8 in

Height h = 5 in

Required:

Find the surface area of the triangular prism.

Step-by-step explanation:

The surface area of the triangular prism is given by the formula:

`A=2* base\text{ area + perimeter of base }*\text{ height}`

The base of the prism is a triangle.

The area of the triangle is given by the formula=

`(1)/(2)* base* height`

So the area of the triangle =

`\begin{gathered} =(1)/(2)*4*3 \\ =6\text{ in}^2 \end{gathered}`

The sides of the triangle are 3 in, 4 in., and 5 in.

The perimeter of the triangle P = 3 + 4+ 5 =12 in.

Thus the surface area of the triangular prism =

`\begin{gathered} A=2*6+12*8 \\ A=12+96 \\ A=108\text{ in.}^2 \end{gathered}`

Final Answer:

The area of the given triangular prism is

`108\text{ in.}^2`