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. Solve (cos x)(cos 2x) = 0 for the interval [0, ππ] x = π/3, x = π/2 x = π/3, x = π/4, x = π/6 x = π/4, x = π/2, x = 3π/4 x = 3 π/4, x = π
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. Solve (cos x)(cos 2x) = 0 for the interval [0, ππ]

x = π/3, x = π/2
x = π/3, x = π/4, x = π/6
x = π/4, x = π/2, x = 3π/4
x = 3 π/4, x = π

User Anton Eliasson
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hello :
(cos x)(cos 2x) = 0

(cos x= 0)0r(cos 2x =0)
sur : [0, π]
1) cos x= 0 : x = π/2
2 ) cos 2x =0 : x = π/4 or x=3π/4
conclusion : x = π/4, x = π/2, x = 3π/4
User Rveach
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