Register

How many real number solutions does the equation have ? 0=-4x^2+7x-8

How many real number solutions does the equation have ? 0=-4x^2+7x-8
157k views
4 votes
How many real number solutions does the equation have ?
0=-4x^2+7x-8

User Simon Elliston Ball
by
8.2k points

1 Answer

4 votes
hello :
-4x² +7x-8 = 0
delta = b²-4ac a=-4 b=7 c=-8
delta = (7)²-4(-4)(-8) =-79
(delta) < 0... no solution in : R
User Nemanja Todorovic
by
7.7k points
← Prev Question Next Question →

No related questions found

Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
Link Copied!