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5 votes
Solve for b.

a = 9b²c



A b=±3ac−−√

B b=±ac√3c

C​ b=±ac√9 ​

D b=±a√3c

2 Answers

4 votes
Expression: a = 9b²c

b² = a/9c

b = √(a/9c)

b = √a/3√c
Or b = 1/3 √(a/c)

In short, Your Answer would be: Option D

Hope this helps!
User Prashant Thorat
by
8.0k points
7 votes

Answer:


b=\pm(1)/(3)\sqrt{(a)/(c)}

Explanation:

Given expression
a=9b^2c

We have to find the value in terms of b

Consider the given expression
a=9b^2c

Divide both side by c, we have


(a)/(c)=9b^2

Again divide by 9 , we have


(a)/(9c)=b^2

Taking square root both side, we have,


\sqrt{(a)/(9c)}=√(b^2)

Simplify , we have,


\sqrt{(a)/(9c)}=b

We know
√(9)=\pm 3

Thus,
b=\pm(1)/(3)\sqrt{(a)/(c)}

User Jamheadart
by
8.1k points