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What is the integral of sec x (sec x + tan x ) dx
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What is the integral of sec x (sec x + tan x ) dx

User Scrooge
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1 Answer

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\sec x(\sec x+\tan x)=\sec^2x+\sec x\tan x

Recall that
(\tan x)'=\sec^2x, and
(\sec x)'=\sec x\tan x.

So,


\displaystyle\int \sec x(\sec x+\tan x)\,\mathrm dx=\tan x+\sec x+C
User Prajo
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