Question

Give the values of a, b, and c from the standard form of the equation (2x + 1)(x - 2) = 0.

A. a = 2, b = -3, c = -2
B. a = 2, b = 5, c = -2
C. a = 3, b = 1, c = -1

Answer 1

Standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0
Distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

A is your answer

Answer 2

Option A - a=2 , b=-3 , c=-2

Explanation:

Given : Equation
`(2x+1)(x-2)=0`

To find : Give the values of a, b, and c from the standard form of the equation?

Solution :

The standard form of the equation is form by multiplying the factors.

Solving by multiplication,

`(2x+1)(x-2)=0`

`2x^2-4x+x-2=0`

`2x^2-3x-2=0`

Comparing with general quadratic equitation,
`ax^2+bx+c=0`

a=2 , b=-3 , c=-2

Therefore, Option A is correct.

The values in standard form of equation are a=2 , b=-3 , c=-2.