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Write the point-slope form of the line that passes through (6, 1) and is perpendicular to a line with a slope of -3

User Ahll
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Hello:
the equation is : y = ax+b
the slope is a : a×(-3) = -1......( perpendicular to a line with a slope of -3)
a = 1/3 y=(1/3)x+b
the line that passes through (6, 1) : 1 = (1/3)(6)+b
b = -1
the equation is : y = (1/3)x-1

User Kurtko
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