Question

How many mL of a 1.75M NaF solution are required to make 681 mL of a 0.234 M NaF solution?

Answer 1

1) List the known and unknown quantities.

Initial conditions.

Concentration: 1.75 M NaF.

Volume: unknown.

Final conditions.

Concentration: 0.234 M NaF.

Volume: 681 mL.

2) Set the equation.

`C1V1=C2V2`

3) Plug in the known quantities and solve for V1.

`(1.75\text{ }M\text{ }NaF)(V1)=(0.234\text{ }M\text{ }NaF)(681\text{ }mL)`
`V1=\frac{(0.234MNaF)(681mL)}{1.75\text{ }M\text{ }NaF}`
`V1=91.06\text{ }mL`

We need 91.06 mL of a 1.75 M NaF solution to make 681 mL of a 0.234 M NaF solution.

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