Question

The length of a rectangle is four times its width.If the perimeter of the rectangle is 80 m, find its area

Answer 1

Area = 256 square meter

EXPLANATIONS

Step 1: Declaration of variables

Let W represent the width of the rectangle and L represent the length.

Step 2: Determine the width and the length

L = 4W ............equ (1)

`\begin{gathered} Perimeter=2\mleft(L+W\mright)=80 \\ 2\mleft(4W+W\mright)=80 \\ 2(5W)\text{ = 80} \\ 10W\text{ = 80} \\ \text{Divide through by 10} \\ W\text{ = }(80)/(10) \\ W\text{ = 8m} \end{gathered}`

from equ (1),

L = 4(8) = 32m

Step 3: Determine the Area

`\text{Area of a rectangle = l}\ast w\text{ = 32}\ast8=256m^2`

Hence, the Area of the rectangle is 256 square meter.