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Consider the polynomial p(x)=16x^4-81y^4. Which of the following are equivalent expressions? Select all that apply

A: (4x^2-9y^2) (4x^2-9y^2)
B: (4x^2-9y^2) (4x^2+9y^2)
C: (4x^2+9y^2) (2x^3y) (2x-3y)
D: (4x^2+9y^2) (2x+3y) (2x+3y)
E: (4x^2+9y^2) (2x+3y) (2x-3y)

2 Answers

5 votes
hello :
p(x)=16x^4-81y^4 = (4x²)²-(9y²)² = (4x²-9y²)(4x²+9y²)...(answer :B)
User Sarit Bahuguna
by
6.3k points
4 votes

Answer:

options (B) and (E) are correct.


16x^2-81y^2=(4x^2+9y^2)(4x^2-9y^2)=(4x^2+9y^2)(2x-3y)(2x+3y)

Explanation:

The given polynomial ,
16x^4-81y^4

We have to choose an equivalent fraction from the given options,

Consider the given polynomial,


16x^4-81y^4 can be written as
(4x^2)^2-(9y^2)^2

Applying identity,
a^2-b^2=(a+b)(a-b) , we get,


(4x^2)^2-(9y^2)^2=(4x^2+9y^2)(4x^2-9y^2)

Again appplying the same identity on second bracket we get,


(4x^2+9y^2)(4x^2-9y^2)=(4x^2+9y^2)((2x)^2-(3y)^2)

Thus,
(4x^2+9y^2)((2x)^2-(3y)^2)=(4x^2+9y^2)(2x-3y)(2x+3y)

Thus, out of given options , options (B) and (E) are correct.

User Keithepley
by
6.0k points