Question

At 35.0°c and 3.00 atm pressure, a gas has a volume of 1.40 l. what pressure does the gas have at 0.00°c and a volume of 0.950 l? which equation should you use?.

Answer 1

The answer is 3.92 sign. digits.

Step-by-step explanation:

Answer 2

Answer : The pressure of gas will be, 3.918 atm and the combined gas law is used for this problem.

Solution :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

`(P_1V_1)/(T_1)=(P_2V_2)/(T_2)`

where,

`P_1` = initial pressure of gas = 3 atm

`P_2` = final pressure of gas = ?

`V_1` = initial volume of gas = 1.40 L

`V_2` = final volume of gas = 0.950 L

`T_1` = initial temperature of gas =
`35^oC=273+35=308K`

`T_2` = final temperature of gas =
`0^oC=273+0=273K`

Now put all the given values in the above equation, we get the final pressure of gas.

`(3atm* 1.40L)/(308K)=(P_2* 0.950L)/(273K)`

`P_2=3.918atm`

Therefore, the pressure of gas will be, 3.918 atm and the combined gas law is used for this problem.