Question

A 10-gram aluminum cube absorbs 677 joules when its temperature is increased from 50°c to 125°

c. what is the specific heat of aluminum? express the answer to the hundredths place

Answer 1

0.90 is the correct answer

Answer 2

Answer : The specific heat of aluminum is,
`0.90J/g^oC`

Solution : Given,

Heat absorbs = 677 J

Mass of the substance = 10 g

Final temperature =
`125^oC`

Initial temperature =
`50^oC`

Formula used :

`Q= m* c* \Delta T`

or,

`Q= m* c* (T_(final)-T_(initial))`

Q = heat absorbs

m = mass of the substance

c = heat capacity of aluminium

`T_(final)` = final temperature

`T_(initial)` = initial temperature

Now put all the given values in the above formula, we get the specific heat of aluminium.

`677g= (10g)* c* (125-50)^oC`

`c=0.9026J/g^oC=0.90J/g^oC`

Therefore, the specific heat of aluminum is,
`0.90J/g^oC`