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a surveyor measures the angle of elevation to a point on a mountain to be 18 degrees. the point on the mountain is horizontally 4 miles away from the surveyor.the vertical change in elevation from the point where the surveyor is standing to the point on the mountain is

User Kasperite
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2 Answers

4 votes

The answer is 1.3 (This is rounded to the nearest hundredth.)


User Rodgdor
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6 votes

Answer:

Using tangent ratio:


\tan \theta = \frac{\text{opposite side}}{\text{Adjacent side}}

As per the statement:

A surveyor measures the angle of elevation to a point on a mountain to be 18 degree.

Angle of elevation
(\theta) = 18 degree.

It is also given that:

the point on the mountain is horizontally 4 miles away from the surveyor.

Let y be the vertical change in elevation from the point where the surveyor is standing to the point on the mountain.

See the diagram as shown below in the attachment

we have;

Opposite side = y miles and adjacent side = 4 miles

Using tangent ratio:


\tan 18^(\circ) = (y)/(4)

then;


0.3249196 = (y)/(4)

Multiply both sides by 4 we have;


1.2996 = y

or


y \approx 1.3 miles.

Therefore, 1.3 miles is the the vertical change in elevation from the point where the surveyor is standing to the point on the mountain

a surveyor measures the angle of elevation to a point on a mountain to be 18 degrees-example-1
User Pankaj Kaundal
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