menu
Qammunity.org
Login
Register
My account
Edit my Profile
Private messages
My favorites
I don't understand how to further answer the question. Can somebody explain with an image of the work?? Solve by completing the square. -3x^2+12x-15=0
Ask a Question
Questions
Unanswered
Tags
Ask a Question
I don't understand how to further answer the question. Can somebody explain with an image of the work?? Solve by completing the square. -3x^2+12x-15=0
asked
Feb 27, 2018
166k
views
2
votes
I don't understand how to further answer the question. Can somebody explain with an image of the work??
Solve by completing the square.
-3x^2+12x-15=0
Mathematics
high-school
Kelly Austin
asked
by
Kelly Austin
8.9k
points
answer
comment
share this
share
0 Comments
Please
log in
or
register
to add a comment.
Please
log in
or
register
to answer this question.
2
Answers
4
votes
-3(x^2+4x-5)
= -3(x-2)^2-3=0
this is ur answer
Igor Alekseev
answered
Feb 28, 2018
by
Igor Alekseev
8.5k
points
ask related question
comment
share this
0 Comments
Please
log in
or
register
to add a comment.
1
vote
-3x^2+12x-15=0
-3x^2+12x =15
-3x^2+12x+36=15
Yugesh
answered
Mar 4, 2018
by
Yugesh
8.5k
points
ask related question
comment
share this
0 Comments
Please
log in
or
register
to add a comment.
← Prev Question
Next Question →
No related questions found
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.
9.4m
questions
12.2m
answers
Categories
All categories
Mathematics
(3.7m)
History
(955k)
English
(903k)
Biology
(716k)
Chemistry
(440k)
Physics
(405k)
Social Studies
(564k)
Advanced Placement
(27.5k)
SAT
(19.1k)
Geography
(146k)
Health
(283k)
Arts
(107k)
Business
(468k)
Computers & Tech
(195k)
French
(33.9k)
German
(4.9k)
Spanish
(174k)
Medicine
(125k)
Law
(53.4k)
Engineering
(74.2k)
Other Questions
How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
Twitter
WhatsApp
Facebook
Reddit
LinkedIn
Email
Link Copied!
Copy
Search Qammunity.org