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5 votes
Someone please help. If you could possibly show your work or tell me what you did that would be wonderful. Thanks!

Someone please help. If you could possibly show your work or tell me what you did-example-1
User Alee
by
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1 Answer

4 votes
Start by getting all of your stuff on the same side.
(4x^2 - 1)/2y - (9y - 5)/3 - z+3y = 0

Then, move the (4x^2 - 1)/2y to the other side of the equation by subtracting it from both sides.
- (9y - 5)/3 - z+3y = -(4x^2 - 1)/2y

Next, get all your ys on the same side of the equation. To do this, multiply both sides by 2y.
2y * (- (9y - 5)/3 - z+3y ) = -(4x^2 - 1)

Simplify this out.
(-18y^2 - 10y)/3 - 2yz +6y^2 = -(4x^2 - 1)

(-18y^2 - 10y)/3 is equal to -6y^2 - 10y/3, so the equation can be rewritten as
-6y^2 - 10y/3 - 2yz +6y^2 = -(4x^2 - 1)
The 6y^2 and -6y^2 cancel eachother out and equal zero.
- 10y/3 - 2yz + 0 = -(4x^2 - 1)

Now we have to move z over. To do this, factor out a y from each term.
y(-10/3 - 2z) = -(4x^2 - 1)

Now, all we have to do is divide both sides by (-10/3 - 2z) to get
y = -(4x^2 - 1)/(-10/3 - 2z)

If we simplify this out, we will find that it is equal to
y = -3(4x^2 - 1)/(-10 - 6z) = -3(4x^2 - 1)/-2(5 + 3z) = 3(4x^2 - 1)/2(5 + 3z)
y = 3(4x^2 - 1)/2(3z + 5)

The answer is D.


User Yogeshagr
by
7.6k points