What is the area of a sector with a central angle of π/3 radians and a radius of 12.4 m? Use 3.14 for π and round your final answer to the nearest hundredth.

Question

asked Dec 26, 2018 164k views

2 Answers

Rok Garbas · Answer 1 · 2019-01-01T15:28:25+0000

Answer:

The area of the sector is 80.47 m².

Explanation:

The area of a sector is

$A=\pi r^2* (\theta)/(360)$

Where, r is radius and θ is central angle in degree.

The radius of the circle is 12.4 m.

Central angle is π/3 radians.

$\theta=(\pi)/(3)* (180)/(\pi)=60^(\circ)$

The area of sector is

A=(3.14)* (12.4)^2* (60)/(360)

$A=80.4677\approx 80.47$

Therefore the area of the sector is 80.47 m².