Question

A small cube with side length 6y is placed inside a larger cube with side length 4x^2. What is the difference in the volume of the cubes?

Answer 1

b

Explanation:

Answer 2

`(64x^(6)-216y^(3))\ units^(3)`

Explanation:

we know that

The volume of a cube is equal to

`V=s^(3)`

where

s is the length side of a cube

Step 1

Find the volume of the smaller cube

we have

`s=6y\ units`

substitute the value in the formula

`V1=(6y)^(3)=216y^(3)\ units^(3)`

Step 2

Find the volume of the larger cube

we have

`s=4x^(2)\ units`

substitute the value in the formula

`V2=(4x^(2))^(3)=64x^(6)\ units^(3)`

Step 3

Find the difference in the volume of the cubes

`V2-V1=(64x^(6)-216y^(3))\ units^(3)`