So already, we know that the acceleration is going to be due to gravity, so it will always be 9.8 m/s/s downwards
For initial velocity, we will need to do kinematics to determine
We know that the acceleration = 9.8 m/s/s
time = 1.33 seconds
and since we know the ball will stop at the very peak of the arc, vf = 0
However, because the ball will have only traveled half way (since we are trying to find the path from initial thrown to the peak of the throw), we will need to divide time by half, and make time = .665 seconds
With these three, we can find max height (also the travel the ball goes) and the initial velocity.
For initial velocity, we can use the formula:
Vf = v0 + at
adjust for v0
v0 = vf - at
plug in what we know
v0 = 0 - (-9.8)(.665) = 6.517 m/s
Now we can solve for max height using
x = vf(t) - 1/2(a)(t^2)
Plug in what we know
x = 0 - 1/2(-9.8)(.665)^2 = 2.1669 meters