Question

you are asked to draw a colored marble out of a box there are 10 red marbles 11 blue marbles and 5 green marbles in the Box what is the probability of drawing a blue marble and then a green marble with a replacement round to three decimal places

Answer 1

There are 10+11+5= 26 colored marble. If we pick 1 blue marble and 1 green marble with replacement, we get

`P(1\text{blue marbol)}\cdot P(1\text{ gr}een\text{ marble)=}(C^(11)_1* C^5_1)/(C^(26)_2)`

where C_n^k is the combinatorial term. Then, we get

`P(1\text{blue marbol)}\cdot P(1\text{ gr}een\text{ marble)=}(11*5)/(325)`

which is equal to

`P(1\text{blue marbol)}\cdot P(1\text{ gr}een\text{ marble)=}0.169`

that is 0.169.