Question

A basket contains 8 pieces of fruit: 3 apples, 3 oranges, and 2 bananas. Jonas takes a piece of fruit at random from the basket, and then Beth takes a piece at random. What is the probability that Jonas will get an orange and Beth will get an apple?

Answer 1

As the basket contains 8 pieces of fruits of which 3 are oranges,

the probability that Jonas will get an orange is 3/8.

Considering Jonas has already got an orange, as 7 fruits are left of which 3 are apple, probability that Beth will get an apple will be 3/7.

Hence the probability that Jonas will get an orange and Beth will get an apple is 3/8*3/7=9/56

Answer: 9/56

Answer 2

`(9)/(56) =16.07`%

Explanation:

To solve this you have to remember that probability is calculated by the next formula:

`Probability=(Desired.outcomes)/(Possible.outcomes)`

You can calculate the probability of two consequent events by multiplying the probability of each one occuring.

So the first one, you have 8 apple sin the basket and 3 of them are oranges, Jonas has to take out 3 out of 8.

`Jonas=(Desired.outcomes)/(Possible.outcomes)\\Jonas=(3)/(8)`

Now there are only 7 fruits in the basket, 3 of them are apples, this means that Beth would have to take out 3 out of 7

`Beth=(Desired.outcomes)/(Possible.outcomes)\\Beth=(3)/(7)`

Now we just have to multiply both probabilities:

`Combined probablilty=((3)/(8)) ((3)/(7) )\\Combined probablilty=((3*3)/(8*7))\\Combined probablilty=((9)/(56))`

So the answer would be that there is a
`(9)/(56)` probability that Jonas and Beth will get an orange and then an apple, when taking fruit out of the basket.