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Solve log(3+2log(1+x)) =0

User Laaposto
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1 Answer

4 votes
Assuming
\log x\equiv\log_(10)x,


\log(3+2\log(1+x))=0

10^(\log(3+2\log(1+x)))=10^0

3+2\log(1+x)=1

2\log(1+x)=-2

\log(1+x)=-1

10^(\log(1+x))=10^(-1)

1+x=\frac1{10}

x=-\frac9{10}
User Ashish Tyagi
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