Question

The average January surface water temperatures (°C) of Lake Michigan from 2000 to 2009 were 5.07, 3.57, 5.32, 3.19, 3.49, 4.25, 4.76, 5.19, 3.94, and 4.34. The data set has the following statistics: x = 4.312 2 = 0.577 What is the standard deviation? Round to the nearest thousandth. 0.333 0.760 2.077 18.593

Answer 1

0.760 I just did this question and this was the answer lol.

Answer 2

`\text{Standard Deviation}=0.76`

Explanation:

The average January surface water temperatures in °C of Lake Michigan from 2000 to 2009 are,

`5.07, 3.57, 5.32, 3.19, 3.49, 4.25, 4.76, 5.19, 3.94,4.34`

The mean
`(\overline{x})` and variance
`(\sigma^2)` are,

`\overline{x}=\sum_(i=1)^(10)a_i=4.312`

`\sigma^2=\sum _(i=1)^n\frac{\left(x_i-\bar{x}\right)^2}{n-1}=0.577`

Standard deviation is the square root of variance.

i.e
`\text{Standard Deviation}=\sigma=√(\sigma ^2)`

`\text{Standard Deviation}=√(0.577)=0.76`