Question

In the following reaction, how many liters of carbon dioxide will be produced if

250 liters of oxygen is used in the combustion of sucrose, given that both gases are at STP?
C12H22O11 + 12O2 → 12CO2 + 11H2O
a. 125 liters b. 500 liters c. 250 liters d. 268.8 liters

Answer 1

for 12 vol.s of o2 the same vol. of co2 is produced.
hence, c.250 litres

Answer 2

Answer: c. 250 liters

Step-by-step explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 Liters at STP and contains avogadro's number
`6.023* 10^(23)` of particles.

To calculate the moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given volume}}{\text {Molar volume}}`

`\text{Number of moles of oxygen}=(250L)/(22.4L)=11.16moles`

Now 12 moles of
`O_2` gives= 12 moles of
`CO_2`

11.6 moles of
`O_2` gives=
`(12)/(12)* 11.6=11.6moles`

Volume of
`CO_2=moles* {\text {Molar volume}}=11.6* 22.4=250L`