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Determine whether the relation is a functiony=x²+xy

User Melika
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By definition, a relation is a function if each Input value (x-value) has one and only one Output value (y-value). Let's remember that a functions show the relationship between variables

In this case, you have the following relation given in the exercise:


y=x^(2)+xy​

This is a function, because each value of "x" has a value "y". Let's solve for the variable "y", as following:


\begin{gathered} y-xy=x^2 \\ y(1-x)=x^2 \\ \\ y=(x^2)/(1-x) \end{gathered}

If you give values to "x", you get the following graph:

Therefore, the relation is a Hyperbolic function.

The answer is: Yes, it is a function.

Determine whether the relation is a functiony=x²+xy-example-1
User Ashwanth Madhav
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