Question

What are the units of AD and BC? What is the area of the trapezoid in square units?

Answer 1

Given:-

A tapezoid.

To find the area.

To find the distance we use the formula,

`d=√((x_2-x_1)^2+(y_2-y_1)^2)`

So now we find the distance of AD is,

`\begin{gathered} d=√((0-16)^2+(13-1)^2) \\ d=√(16^2+12^2) \\ d=√(256+144) \\ d=√(400) \\ d=20 \end{gathered}`

So the distance of AD is 20.

So now we find the distance of BC,

`\begin{gathered} d=√((5-1)^2+(3-6)^2) \\ d=√(4^2+(-3)^2) \\ d=√(16^+9) \\ d=√(25) \\ d=5 \end{gathered}`

So the distance of BC is 5.

So now the area of trapezoid is,

`\begin{gathered} A=(a+b)/(2)(h) \\ A=(20+5)/(2)(5) \\ A=(25)/(2)(5) \\ A=(125)/(2) \\ A=62.5 \end{gathered}`

So the required area is 62.5 sq units.