Question

Find an equation of variation in which y varies inversely as x and y=6.25 and x=0.32. Then find the value of y when x=17.

Answer 1

we know y = 6.25 when x = 0.32

let y = k/x

so we can solve for k:

6.25 = k/3

k = 3*6.25 = 18.75

Now we have y= 18.75/x

So, when x = 17

y = 18.75/17 = 1.103