Question

Jessica is planning to paint her room. It measures 11 feet by 13 feet and has 8 foot ceilings. One long wall and one short wall each has a window that measures 3 feet by 4 feet. One short wall has two doors that measures 7 feet by 4 feet. Each can of paint will cover 375 square feet. How many cans of paint will Jessica need to purchase if she wants to do paint two coats on the walls?

Answer 1

Answer: 2.00 cans

Step-by-step explanation

Given

• 11 feet by 13 feet and has 8 foot ceilings.

,

• One long wall and one short wall each has a window that measures 3 feet by 4 feet.

,

• One short wall has two doors that measure 7 feet by 4 feet.

,

• Each can of paint will cover 375 square feet.

Procedure

We have to get the area of a window and door.

• Calculating the area of a window ,(Aw)

`A_w=3*4=12ft^2`

• Calculating the area of a door ,(Ad)

`A_d=7*4=28`

Now, we have to calculate the area of each side and the roof (considering that she will not paint the floor).

• Calculating the total area of the large side ,(AL)

`A_L=13*8=104ft^2`

• Calculating the total area of the small side ,(As)

`A_s=11*8=88ft^2`

• Calculating the total area of the ceiling ,(Ac)

`A_c=11*13=143ft^2`

Then, the total area would be the sum of the sides plus the ceiling. However, we have to subtract the doors and windows.

• Calculating the total area ,(AT)

`A_T=A_L+A_L+A_s+A_s+A_c`

Replacing the values by adding the subtraction of the windows.

`A_T=104+(104-12)+88+(88-12)+143`

Replacing the values by adding the subtraction of the doors.

`A_T=104+(104-12)+(88-2\cdot28)+(88-12)+143`

As she wants to paint two coats on the walls, we have to multiply each term of the walls times two:

`A_T=2\cdot104+2\cdot(104-12)+2\cdot(88-2*28)+2\cdot(88-12)+143`

Simplifying:

`A_T=2\cdot104+2\cdot92+2\cdot32+2\cdot76+143`
`A_T=751ft^2`

Finally, as each can of paint will cover 375 square feet, we have to divide this quantity:

`A_T=(751)/(375)\approx2.00`