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The area on the wall covered by a rectangle poster is 320 square inches.The length of the poster is 1.25 times longer than the width of the poster. What are the dimensions of the poster?

2 Answers

2 votes
If width is X, then length is 1.25X
1.25X·X=320
1.25X²=320
X²=256
X=16 or X=-16(not this one...)
width=16in
length=16x1.25=20in
Those are your answers.
User Mark McClure
by
8.4k points
6 votes

Answer:

Length = 20 inches

Width = 16 inches

Explanation:

The area on the wall covered by a rectangle poster is 320 square inches.

The length of the poster is 1.25 times longer than the width of the poster.

Let x be the width of the poster.

Length of the poster = 1.25x

Area of a rectangular poster is


Area=length* width


Area=1.25x* x


320=1.25x^2

Divide both sides by 1.25.


(320)/(1.25)=x^2


256=x^2

Taking square root on both sides.


\pm 16=x

The dimensions can not be negative. So, x=16.

Length of the poster = 1.25(16)=20

Therefore, the length of the poster is 20 inches and width of the poster is 16 inches.

User Ryan French
by
8.2k points

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