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4 votes
How many grams of AgNO3 are needed to prepare a 0.25 m solution in 500 grams of water?

Question 2 options:


125 g


0.125g


21.25 g


170g

User Jovon
by
8.3k points

1 Answer

4 votes
Volume = V = 250ml = 0.25 L
M = 0.135M
Molar mass of AgNO3 = 108+14+3*16 = 170

M = mole/V
mole = 0.135*0.25 = 0.03375 mole

mole = mass/molar mass

mass = 0.03375 * 170 = 5.7375 gr
User Etep
by
8.2k points