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Write an equation of the line that passes through (2, −1) and is parallel to the line y=−3x+8.

An equation of the parallel line is y=

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Answer:

Explanation:

The slope of the line in question is the same as the slope of the line parallel to it. Using y = mx + b, where m is the slope, we find the slope of our line is -3.

Using the pt-slope form, y - y1 = m( x - x1), we get y - (-1) = -3( x - 2) or y + 1 = -3x + 6. Which leads us to y = -3x + 5. QED

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