One way to evaluate f(g(3))f(g(3))f, left parenthesis, g, left parenthesis, 3, right parenthesis, right parenthesis is to work from the "inside out". In other words, let's evaluate g(3)g(3)g, left parenthesis, 3, right parenthesis first and then substitute that result into fff to find our answer.Let's evaluate g({3})g(3)g, left parenthesis, 3, right parenthesis.\begin{aligned}g(x)&=x^3+2\\\\ g(3)&=({3})^3 +2~~~~~~~~~~~~~~~~~~~\small{\gray{\text{Plug in }x={3.}}}\\\\ &={29}\end{aligned}g(x)g(3)=x3+2=(3)3+2 Plug in x=3.=29