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Hello, I need help with this precalculus homework question, please?HW Q9

Hello, I need help with this precalculus homework question, please?HW Q9-example-1
Hello, I need help with this precalculus homework question, please?HW Q9-example-1
Hello, I need help with this precalculus homework question, please?HW Q9-example-2
User Tringuyen
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1 Answer

19 votes
19 votes

Solution

- The question would like us to determine the difference expression that corresponds to the following logarithm


\log_a((M)/(N))

- In order to solve this question, we should apply the Law of Logarithm which states that:


\log A-\log B=\log((A)/(B))

- Applying this law, we have:


\begin{gathered} \text{ Let A from the formula be M and Let B from the formula be N from the question} \\ Note\text{ that }a\text{ in the question is represented by 10 from the formula. The base 10 in logarithm is usually not } \\ \text{ indicated} \\ \\ \log_a((M)/(N))=\log_aM-\log_aN \end{gathered}

Final Answer

The answer to the question is


\operatorname{\log}_(a)((M)/(N))=\operatorname{\log}_(a)M-\operatorname{\log}_(a)N

User Davypough
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2.9k points