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Find the dimensions of a rectangle with area 2,197 m2 whose perimeter is as small as possible.

User Asmundur
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The area of a rectangle is calculated by multiplying its length and width. That is,
A = L x W
Given that area is 2,197, the width is 2197/L. The perimeter on the other hand is the twice the sum of the dimensions. That is,
P = 2L + 2(2197/L)
Differentiating the equation and equating the differential to zero.
dP = 2 + 4394(-1/L²) = 0
Solving for L will give us an answer of 46.87 m. Thus, the length and the width of the rectangle are approximately 46.87 m both.
User Boris Azanov
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