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Find k so that 25x^2 + 40x + k is the square of the binomial.

2 Answers

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k= 16

25x^2+40x+16x comes to be (5x+4)^2.
User Stueynet
by
7.4k points
2 votes

Answer:

The value of k is, 16

Explanation:

Using the square of the binomial.


(a+b)^2 = a^2+2ab+b^2 .....[1]

Given the polynomial


25x^2+40x+k

On comparing with [1] we have;


a^2 = 25x^2


2ab = 40x and


b^2 = k

then;


a=√(25x^2) = 5x

Solve for b:


2ab =40x


2 \cdot 5x \cdot b =40x


10xb = 40x

Divide both sides by 10x we have;


b = 4

it is given that:


k = b^2 = 4^2 = 16

then,

we get the square of the binomial;


(5x+4)^2 = 25x^2+40x+16

Therefore, the value of k is, 16

User A Haworth
by
8.0k points

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