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If a ball is thrown into the air with a velocity of 42 ft/s, its height (in feet) after t seconds is given by y = 42t − 16t2. Find the velocity when t = 1.

User Alaroff
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2 Answers

4 votes
velocity is found using the first derivitive, y'=42-32t
evaluating this as t=1 gives the velocity after 1 second which is 10ft.
User Piyush Sahu
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3 votes
I'm pretty sure its 10
User Abdellah OUMGHAR
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