menu
QAmmunity.org
Login
Register
My account
Edit my Profile
Private messages
My favorites
Register
Ask a Question
Questions
Unanswered
Tags
Categories
Ask a Question
Can somebody help me find the 11th term of the geometric sequence 6,30,150,750?
asked
Jul 10, 2018
65.6k
views
4
votes
Can somebody help me find the 11th term of the geometric sequence 6,30,150,750?
Mathematics
high-school
Vickey
asked
by
Vickey
6.3k
points
answer
comment
share this
share
0 Comments
Please
log in
or
register
to add a comment.
Please
log in
or
register
to answer this question.
1
Answer
7
votes
geometrice
an=a1(r)^(n-1)
a1=first term
r=common ratio
n=which term
we see first term is 6
common ratio is a term divided by the previous term
30/6=5
r=5
an=6(5)^(n-1)
11th term
a11=6(5)^(11-1)
a11=6(5)^10
a11=6(9765625)
a11=58593750
the 11th term is 58593750
Joseph Wood
answered
Jul 13, 2018
by
Joseph Wood
6.4k
points
ask related question
comment
share this
0 Comments
Please
log in
or
register
to add a comment.
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.
6.5m
questions
8.7m
answers
Other Questions
What is 0.12 expressed as a fraction in simplest form
Solve using square root or factoring method plz help!!!!.....must click on pic to see the whole problem
What is the initial value and what does it represent? $4, the cost per item $4, the cost of the catalog $6, the cost per item $6, the cost of the catalog?
What is distributive property ?
What is the measure of xyz
Twitter
WhatsApp
Facebook
Reddit
LinkedIn
Email
Link Copied!
Copy
Search QAmmunity.org