Question

You just got a free ticket for a boat ride, and you can bring along 3 friends! Unfortunately, you have 5 friends who want to come along. How many different groups of friends could you take with you?

Answer 1

To determine how many different groups of 3 friends you can bring along from 5 friends, you calculate combinations using the formula C(5, 3) = 5! / (3! (5 - 3)!), which equals 10. Therefore, there are 10 different groups of 3 friends that can be selected.

Step-by-step explanation:

The question is asking how many different groups of 3 friends you can select from a total of 5 friends, which is a combinatorial mathematics problem involving combinations. To solve this problem, we use the combinations formula:

C(n, k) = n! / (k! (n - k)!)

where:

• n is the total number of items,
• k is the number of items to choose,
• ! symbol denotes factorial.

So with 5 friends and choosing 3, the calculation is as follows:

C(5, 3) = 5! / (3! (5 - 3)!)

C(5, 3) = (5 × 4 × 3 × 2 × 1) / ((3 × 2 × 1) × (2 × 1))

C(5, 3) = (120) / (6 × 2)

C(5, 3) = 120 / 12

C(5, 3) = 10

Thus, there are 10 different groups of 3 friends that you can bring along with you on the boat ride.

Answer 2

I believe the answer is 2 because it goes by 3