Determine the magnitude and direction of vector a = (3,8) Round to the nearest tenths. |a| =theta =

Ahmed Nasser asked Feb 12, 2023

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Ahmed Nasser asked Feb 12, 2023

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Recall the definitions of the magnitude and direction of a vector:

$\begin{gathered} \parallel a\parallel=\sqrt[]{3^2+8^2}=\sqrt[]{73}=8.5 \\ \theta=\tan ^(-1)((8)/(3))=69.4^(\circ) \end{gathered}$

Balkondemiri answered Feb 17, 2023

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