25.2k views
4 votes
What volume of a 3.0 M stock solution of H2SO4 is needed to prepare 2.8 L of a 1.6 M H2SO4 solution?

User Sophonias
by
8.2k points

2 Answers

4 votes
Use M1V1 = M2V2 to solve
3(V1) = 2.8 * 1.6
3(V1) = 4.48
V1 = 1.493 L of stock solution
User Grzkv
by
8.4k points
3 votes

Answer: The volume of stock solution needed is 1.5 L

Step-by-step explanation:

To calculate the molarity of the diluted solution, we use the equation:


M_1V_1=M_2V_2

where,


M_1\text{ and }V_1 are the molarity and volume of the stock solution


M_2\text{ and }V_2 are the molarity and volume of diluted solution

We are given:


M_1=3M\\V_1=?L\\M_2=1.6M\\V_2=2.8L

Putting values in above equation, we get:


3* V_1=1.6* 2.8\\\\V_1=1.5L

Hence, the volume of stock solution needed is 1.5 L

User Cikenerd
by
8.0k points