181k views
5 votes
Calculate the change in energy of an atom that emits a photon of wavelength 2.21 meters. (Planck’s constant is 6.626 x 10-34 joule seconds, the speed of light is 2.998 x 108 m/s)

8.9886 x10-26 joules
4.8844 x 10-42 joules second
1.9864 x 10-25 joules
1.4643 x 10-33 joules /second

1 Answer

3 votes
The answer is C. 1.9864 x 10-25 joules
User Abhim
by
6.6k points