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If 82.5 g of potassium sulfide react, how many moles of K2S react
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If 82.5 g of potassium sulfide react, how many moles of K2S react

User Adam Cataldo
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1 Answer

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One mole of K2S = 110.27g, so 3.3 moles K2S=363.89 g
First find the molar mass of K2S:
K2 x 39.10 = 78.20
S1 x 32.07= 32.0778.20 + 32.07 = 110.27g3.3 moles K2S x 110.27g/mol = 363.89g
User Giacomo Torricelli
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