Question

assume a sample is used to estimate a population proportion P. find the margin of error E that corresponds to the given statistics and confidence level. round margin of error to four decimal places99% confidence; n=6500, x=1950

Answer 1

The margin of error of proportion is: E = 0.0146

How to find the margin of error of proportion?

The formula to find the margin of error of proportion is:

E = z
`\sqrt{((p(1 - p)))/(n) }`

where:

p is sample proportion

n is sample size

z is z-score at confidence level

Thus:

p = x/n = 1950/6500

p = 0.3

z at 99% confidence level is: 2.58

Thus:

E = 2.58
`\sqrt{((0.3(1 - 0.3)))/(6500) }`

E = 0.0146

Answer 2

99% confidence; n=6500, x=1950

Assume that a sample is used to estimate a population proportion p. Find the margin of error E that corresponds to the given statistics and confidence level. Round the margin of error to four decimal places.

The margin of error is known to be the maximum likely difference between the point estimate of a parameter and the actual value of the parameter. For one population proportion, p, the margin of error is computed as follows:

Margin of Error =